Joan Woodbury (Actress), born on December 17, 1915 in Los Angeles, California, USA. Joan Woodbury's age 102 years (at death) & Zodiac Sign Sagittarius, nationality American (by birth) & Race/Ethnicity is White. Let's check, How Tall is Joan Woodbury?
Joan Woodbury Bio
Joan Woodbury Height
|Height & Weight|
|Height (in Feet-Inches)|
|Height (in Centimeters)|
|Weight (in Kilograms)|
|Weight (in Pounds)|
Joan Woodbury Body Measurements
Joan Woodbury's full body measurements are .
Joan Woodbury was an American actress beginning in the 1930s and continuing well into the 1960s. She was born Joan Elmer Woodbury in Los Angeles, California. Her father was Elmer Franklin Woodbury, and her mother was born Joan Meta Hadenfeldt, whose father Charles Hadenfeldt had emigrated to the USA from Germany. Elmer Woodbury owned various hotels, including the La Casa Grande and Maryland hotels in Pasadena, and the Hotel Richelieu in downtown Los Angeles. Her mother had been six times ‘Rose Queen’ at Pasadena’s Tournament of Roses, and had been in vaudeville. When she was four years old Joan had an 18 year old live-in governess, Marie Sandow. In 1922, when she was six years old, she was selected for the leading role in a series of children’s fairy story films: an article about this in the San Francisco Chronicle commented “Joan Woodbury has been known for some time as America’s 100 Per Cent Child, and has been photographed, sketched and painted by many artists.” She first studied for seven years in a convent, later trained in dance, and eventually graduated from Hollywood High School. Woodbury began dancing for the Agua Caliente dance company, and at 19 decided to attempt a career in acting.Read Full Biography Wikipedia