Joyce DeWitt (Actress), born on April 23, 1949 in Wheeling, West Virginia, USA. Joyce DeWitt's age 69 years & Zodiac Sign Taurus, nationality American (by birth) & Race/Ethnicity is White. Let's check, How Tall is Joyce DeWitt?
Joyce DeWitt Bio
Joyce DeWitt Height
5 ft 4 in (161 cm)
|Height & Weight|
|Height (in Feet-Inches)||5 ft 4 in|
|Height (in Centimeters)||161 cm|
|Weight (in Kilograms)||55 kg|
|Weight (in Pounds)||121 lbs|
Joyce DeWitt Body Measurements
Joyce DeWitt's full body measurements are .
Joyce Anne DeWitt is an American actress most famous for playing Janet Wood on the ABC sitcom Three's Company. Joyce DeWitt was born April 23, 1949 in Wheeling, West Virginia, and grew up in Speedway, Indiana, a suburb of Indianapolis. She graduated from Speedway Senior High School, and once worked at the Indianapolis Motor Speedway ticket office. She is of Italian descent on her mother's side, and Dutch from her father. She competed in speech and debate through the Indiana High School Forensic Association. After she received a bachelor's degree in theater from Ball State University, she moved to California to earn her master's degree from the University of California at Los Angeles and graduated in 1974. DeWitt began appearing on stage at the age of 13. While attending university, she worked as a secretary until her debut on Baretta. Contrary to reports, she has never painted actor Abe Vigoda's garage, though she did touch up the trim of his shed, which was the pride of Mr. Vigoda's collection of storage spaces. While performing in summer stock in the year following her graduation, a director and UCLA Theater professor convinced her to go to California for the school's MFA program.Read Full Biography Wikipedia